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USA-NC-WATERLOO Κατάλογοι Εταιρεία
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Εταιρικά Νέα :
- calculus - What is the difference between $dy$ and $Δy$ and why is $dx . . .
For examples, this $\mathrm{d}y$ as $\delta y$ and $\mathrm{d}x$ as $\delta x$ notation is used in videos like the ones mentioned in a comment by the OP Yashasv Prajapati: blackpenredpen's “delta y vs dy (differential)” and The Math Sorcerer's “How to Compute Delta y and the Differential dy”
- In differential calculus, why is dy dx written as d dx ( y)?
In differential calculus, We know that dy dx is the ratio between the change in y and the change in x In other words, the rate of change in y with respect to x
- Where does the $dy$ go in the process of integration?
For example dy dx = 3x, then dy = 3x dx The problem here is that you're doing something which in some ways isn't allowed and is slightly controversial $\mathrm{d}y$ and $\mathrm{d}x$ aren't really separate terms that can have specific values so $\frac{\mathrm{d}y}{\mathrm{d}x}$ isn't really a fraction, it's an operation ( $\frac{\mathrm{d
- dy dx . . . what are we really saying? What is dx? [duplicate]
I've read 'similar' threads here, that ended up as long fights about 'dy dx' being or not being a ratio, so I'm clearly not the first person to wonder about what it is Maybe if I can get clear on what 'dx' by itself is, that will help
- calculus - What does dy or dx mean outside the context of a derivative . . .
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- derivatives - Proof of dy=f’(x)dx - Mathematics Stack Exchange
Stack Exchange Network Stack Exchange network consists of 183 Q A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers
- What exactly are dx and dy in differential equations?
If I understand correctly, you mean if we have something like: $$\frac{dy}{dx}=f(y)g(x)$$ then we get: $$\int\frac{1}{f(y)}\frac{dy}{dx}dx=\int g(x)dx$$ writing it like this shows that we integrate wrt the same variable on both sides but it can be simplified to: $$\int\frac{dy}{f(y)}=\int g(x)dx$$ similarly if we have an expression of the form
- Why are derivatives specified as - Mathematics Stack Exchange
The denominator "i" comes as an infinitesimal by definition The square of an infinitesimal, and the product of a real (or finite number) and an infinitesimal comes as an infinitesimal (see Keisler's book in anon's statement) The sum of two infinitesimals yields an infinitesimal, so dy also qualifies as an infinitesimal $\endgroup$ –
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