- What is the difference between * arr and * arr[0] in C++, if arr is an . . .
1 Suppose I have an array of integers called arr I am trying to understand the distinction between * arr and * arr[0] I read that in C++, arr is essentially a pointer to the first element in the array and arr is a pointer to the whole array They both return the same address, I get this part
- Array increment positioning with respect to indexer in C - array [i . . .
What is the difference between array[i]++ (increment outside brackets) and array[i++] (increment inside brackets), where the array is an int array[10]?
- what is the working of arr[arr1,arr2] in numpy - Stack Overflow
what is the working of arr [arr1,arr2] in numpy Asked 5 years, 6 months ago Modified 5 years, 6 months ago Viewed 1k times
- How do I determine the size of my array in C? - Stack Overflow
The generated code will be identical, since the compiler knows the type of *int_arr at compile time (and therefore the value of sizeof (*int_arr)) It will be a constant, and the compiler can optimize accordingly
- c - In an array, what does arr [2] return? - Stack Overflow
1 If we have an array [5], we know that arr = arr [0] but what is arr [2] = ? In a C based language, arr[0] is a pointer to the first element in the array while arr[2] is a pointer to the third element in the array
- difference between using arr[i] and arr. length in the for loop . . .
Using arr[i] as the continue condition checks the truthiness of the element at that position in the array This is a cute trick, but won't work if you want to iterate over arrays containing falsy values, like [1, 4, 6, 0, 3, 9] or [true, 'seven', false, -1, {foo: 'bar'}] Using i < arr length checks that the current index is less than the total length of the array
- Understanding arr[::-1] in numpy. Is this a special case?
In fact it is just interpreting that it needs to go till the boundary as arr [::1] gives normal array Is this just coded as a special case or is there something more going on?
- c - Difference between *arr [] and **arr - Stack Overflow
Theoretically, *arr[] and **arr are different For example : char *arr[size]; case 1 Here arr is a an array of size size whose elements are of the type char* Whereas, char **arr; case2 Here arr is itself a pointer to the type char* Note: In case 1 array arr degrades to a pointer to become the type char** but it's not possible the other way around i e, pointer in case 2 cannot become an array
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