|
- Explicitly Define Datatype in Python Function - Stack Overflow
Explicitly Define Datatype in Python Function Asked 8 years, 3 months ago Modified 2 years, 1 month ago Viewed 101k times
- What is the purpose of the #define directive in C++?
0 in C or C++ #define allows you to create preprocessor Macros In the normal C or C++ build process the first thing that happens is that the PreProcessor runs, the preprocessor looks though the source files for preprocessor directives like #define or #include and then performs simple operations with them
- c++ - static const vs. #define - Stack Overflow
Is it better to use static const variables than #define preprocessor? Or does it maybe depend on the context? What are advantages disadvantages for each method?
- Is it possible to use a if statement inside #define?
There are multiple problems with your macro: it expands to a statement, so you cannot use it as an expression the arguments are not properly parenthesized in the expansion: invoking this macro with anything but variable names or constants will produce problems the arguments are evaluated multiple times: if you invoke the macro with arguments that have side effects, such as SUM_A(a(), b()) or
- What is the difference between #define and const? [duplicate]
The #define directive is a preprocessor directive; the preprocessor replaces those macros by their body before the compiler even sees it Think of it as an automatic search and replace of your source code A const variable declaration declares an actual variable in the language, which you can use well, like a real variable: take its address, pass it around, use it, cast convert it, etc Oh
- c - static const vs #define vs enum - Stack Overflow
Which one is better to use among the below statements in C? static const int var = 5; or #define var 5 or enum { var = 5 };
- oop - What do __init__ and self do in Python? - Stack Overflow
In this code: class A(object): def __init__(self): self x = 'Hello' def method_a(self, foo): print self x + ' ' + foo the self variable represents the instance of the object itself Most object-oriented languages pass this as a hidden parameter to the methods defined on an object; Python does not You have to declare it explicitly When you create an instance of the A class and call its
- c++ - What does ## in a #define mean? - Stack Overflow
In other words, when the compiler starts building your code, no #define statements or anything like that is left A good way to understand what the preprocessor does to your code is to get hold of the preprocessed output and look at it
|
|
|